Rams, Donald agree on reported six-year, $135M deal

According to multiple reports, the deal is for six years and $135 million.

Defensive tackle Aaron Donald and the Los Angeles Rams have finally reached agreement on a long-term extension, and the All-Pro was on the field for workouts Friday afternoon.

According to multiple reports, the deal is for six years and $135 million.

Donald, 27, reportedly will also receive a $40 million signing bonus and $87 million in guaranteed money.

The deal makes Donald the highest-paid defensive player in history at an annual average just over $22 million. Denver linebacker Von Miller previously led all NFL defenders at $19 million annually.

"Everyone with common sense knew that at minimum, Aaron Donald was going to be the highest-paid defensive player in football," Rams general manager Les Snead said, per the team's web site.

The Rams created about $7 million of 2018 cap space on Thursday by restructuring the contracts of left tackle Andrew Whitworth and wide receiver Robert Woods, bringing their total cap space to $10.1 million, per Spotrac.

The Rams open their season on Sept. 10 against the Oakland Raiders, and Donald will play.

"We have a strategic plan over the next couple weeks to get him up to speed," Rams head coach Sean McVay said, per the team web site.

Donald, the reigning Defensive Player of the Year, earned just over $10.1 million from 2014-17, combined, and is due $6.9 million this season, the fifth-year option of his rookie deal. The 27-year-old has made the Pro Bowl in each of his four seasons and has three first-team All-Pro nods.

The Rams have been able to reach deals with other core players recently, extending both wideout Brandin Cooks and running back Todd Gurley in a span of a week before training camp opened. They consistently had been vocal about their plan to re-sign Donald.

(This story has not been edited by Devdiscourse staff and is auto-generated from a syndicated feed.)